PA_JH02b
Premises:
(forall ?X (not (= 0 (succ ?X)))) (forall (?X ?Y) (=> (= (succ ?X) (succ ?Y)) (= ?X ?Y))) (forall ?X (= (+ ?X 0) ?X)) (forall (?X ?Y) (= (+ ?X (succ ?Y)) (succ (+ ?X ?Y)))) (forall ?X (= (* ?X 0) 0)) (forall (?X ?Y) (= (* ?X (succ ?Y)) (+ (* ?X ?Y) ?X))) (forall (?X ?Y) (= (+ ?X ?Y) (+ ?Y ?X))) (forall (?X ?Y) (= (* ?X ?Y) (* ?Y ?X)))
Conclusion:
(forall ?X (= (* (succ 0) (succ ?X)) (succ ?X)))
Proof Trace